Wire gauge calculations
Wire diameter calculations
The n gauge wire diameter dn in inches (in) is equal to 0.005in times 92 raised to the power of 36 minus gauge number n, divided by 39:
dn (in) = 0.005 in × 92(36-n)/39
The n gauge wire diameter dn in millimeters (mm) is equal to 0.127mm times 92 raised to the power of 36 minus gauge number n, divided by 39:
dn (mm) = 0.127 mm × 92(36-n)/39
Wire cross sectional area calculations
The n gauge wire’s cross sercional area An in kilo-circular mils (kcmil) is equal to 1000 times the square wire diameter d in inches (in):
An (kcmil) = 1000×dn2 = 0.025 in2 × 92(36-n)/19.5
The n gauge wire’s cross sercional area An in square inches (in2) is equal to pi divided by 4 times the square wire diameter d in inches (in):
An (in2) = (π/4)×dn2 = 0.000019635 in2 × 92(36-n)/19.5
The n gauge wire’s cross sercional area An in square millimeters (mm2) is equal to pi divided by 4 times the square wire diameter d in millimeters (mm):
An (mm2) = (π/4)×dn2 = 0.012668 mm2 × 92(36-n)/19.5
Wire resistance calculations
Resistivity (ρ(Ω·m))
- copper: 1.72e-8,
- aluminum: 2.82e-8,
- carbon Steel: 1.0e-7,
- electrical Steel: 5.0e-7,
- gold: 2.44e-7,
- nichrome: 1.10e-6,
- nickel: 6.99e-7,
- silver: 1.59e-8
The n gauge wire resistance R in ohms per kilofeet (Ω/kft) is equal to 0.3048×1000000000 times the wire’s resistivity ρ in ohm-meters (Ω·m) divided by 25.42 times the cross sectional area An in square inches (in2):
Rn (Ω/kft) = 0.3048 × 109 × ρ(Ω·m) / (25.42 × An (in2))
The n gauge wire resistance R in ohms per kilometer (Ω/km) is equal to 1000000000 times the wire’s resistivity ρ in ohm-meters (Ω·m) divided by the cross sectional area An in square millimeters (mm2):
Rn (Ω/km) = 109 × ρ(Ω·m) / An (mm2)
Note:
- Diameter and cross sectional area do not include the insulation.
- Results may change with real wires: different resistivity of material and number of strands in wire
- 20°C or @ 68°F